Physics Optics

Physics Optics

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Physics: optics of lenses and mirrors (9)


Can someone Please help me with physics- (OPTICS)?

A concave mirror has a focal length of 0.120 m. This mirror forms an image located 0.360 m in front of the mirror.
(a) where is this object located?
(b) What is this magnification?
(c) Is this image real or is it virtual?
(d) Is this image upright or is it inverted?
(e) Is this image enlarged or is it reduced in size?

Let:
u be the object distance,
v be the image distance,
f be the focal length of the mirror,
m be the magnification.

With the real is positive sign convention, f is +ve for a concave mirror.

(a)
The equation is:
1 / u + 1 / v = 1 / f

1 / u + 1 / 0.360 = 1 / 0.120
u = 0.18 m.

Note in respect of answers (b)-(d):
If you use the equation m = v / u for magnification, then a positive result means the image is real.

If you use m = - v / u, a positive result means the image is upright.

Either way a real image is inverted, and a virtual image is upright.

(b)
m = 0.360 / 0.18 = 2.00.

(c)
Real.

(d)
Inverted.

(e)
A magnification with an absolute value greater than 1 means the image is enlarged.