May 4, 2010
Optics Bench
Optics Bench
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Mountain Woods Aspen 6' Dining Set With 2 Chairs, 2 Benches
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Mountain Woods Aspen 6' Upholstered Dining Set With Bench - The Woods
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Edroy U66-2 Stereoptic Dual Lens 6x6
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Ginsberg Scientific 7-1404-20 Compact Optical Bench
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Allen Company 4 Way Adjustable Deluxe Binocular Strap, Black
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Sun Optics USA SM1006 Bubble Bore Level Fits Weaver Rail
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Optics: Learning by Computing, with Examples Using Maple, MathCad®, Matlab®, Mathematica®, and Maple® (Undergraduate Texts in Contemporary Physics)
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The Optical Bench (Popular Optics Library no. 9085)
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Wheeler 89-Piece Deluxe Gunsmithing Screwdriver Set
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Grip Tools 100 Piece Utility Blade With Bench Dispenser Standard Size Utility Blades
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Military LED Flashlight
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Optic Bench
Testing the Lens Formula?
My labscript on optics, in the the experiment aims to find the focal length of a plano-convex lens, states the following:
"Use your ruler to measure the distances s (object-to-lens) and s' (image-to-lens) values over as wide as the length of the bench allows. Use 5 or 6 object-to-image distances. For each object-to-image distance, there will be 2 positions of the lens that yields a sharp image, so your graph (1/s vs 1/s') wil consist of 10-12 points.
How exactly are there 2 positions for a given object-to-image distance?
The first answer makes sense. However, when I read that paragraph from my labscript, it implies to me that there are two positions that form the real image on the screen, especially as the remainder of the contents of this scrtipt states only about measuring real images. Am I missing something?
*script, sorry
Your lens is only being used to produce real images on a screen.
Provided the total distance from object to image is greater than 4 times the lens's focal length there will be two, symmetrical positions.
e.g. s=15 and s'=35, and then s=35 and s'=15
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